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数组变MaxTree-java

创建时间:2015-11-22 投稿人: 浏览次数:283
public int[] buildMaxTree(int[] A, int n) {
        // write code here
        if (A == null || n < 1) {
            return null;
        }
        Stack<Integer>  findStack = new Stack<Integer>();
        Integer[] leftMax  = new Integer[n];
        Integer[] rightMax = new Integer[n];
         
         
        for (int i = 0; i < n; i++) {
            while (!findStack.empty() && A[findStack.peek()] <= A[i]) {
                findStack.pop();
            }
            if (findStack.empty())
                leftMax[i] = null;
            else
                leftMax[i] = findStack.peek();
            findStack.push(new Integer(i));
        }
         
        while (!findStack.empty()) {
            findStack.pop();
        }
         
        for (int i = n - 1; i >= 0; i--) {
            while (!findStack.empty() && A[findStack.peek()] <= A[i]) {
                findStack.pop();
            }
            if (findStack.empty())
                rightMax[i] = null;
            else
                rightMax[i] = findStack.peek();
            findStack.push(new Integer(i));
        }
         
        int[] res = new int[n];
        int j = 0;
        for (int i = 0; i < n; ++i) {
            if (leftMax[i] != null && rightMax[i] != null) {
                if (A[leftMax[i]] < A[rightMax[i]])
                    res[j++] = leftMax[i];
                else
                    res[j++] = rightMax[i];
            }
            else if (leftMax[i] != null && rightMax[i] == null) {
                res[j++] = leftMax[i];
            }
            else if (leftMax[i] == null && rightMax[i] != null) {
                res[j++] = rightMax[i];
            }
            else {
                res[j++] = -1;
            }
        }
         
        return res;
}

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