c++ unique函数返回值

std::unique

功能：对有序的容器重新排列，将第一次出现的元素从前往后排，其他重复出现的元素依次排在后面

返回值：返回迭代器，迭代器指向的是重复元素的首地址

看不懂表达的看看下面这个简图：

有序的容器：

1

1

2

3

3

4

4

4

5

6

unique处理过的容器：

unique	unique	unique	unique	unique	unique	迭代器指向的地址
1	2	3	4	5	6	1	3	4	4

代码如下：

#include<iostream>
#include<string>
#include <algorithm>
#include <vector>

using namespace std;
typedef vector <string> VECTOR_STRING;

void printVec(VECTOR_STRING& vec)
{
	for(size_t nItem = 0; nItem < vec.size(); nItem++)
	{
		cout << "Name[" << nItem << "] = " ";
		cout << vec[nItem] << " " " << endl;
	}
	cout << endl;
}

int main()
{
	VECTOR_STRING vecNames;
	vecNames.push_back("john");
	vecNames.push_back("bob");
	vecNames.push_back("john");
	vecNames.push_back("vctor");
	vecNames.push_back("vctor");
	vecNames.push_back("jim");
	vecNames.push_back("bob");
	vecNames.push_back("jim");

	cout << "the initial contents are:" << endl;
	printVec(vecNames);

	sort(vecNames.begin(), vecNames.end());

	cout << "after sort(), contents are:" << endl;
	printVec(vecNames);

	VECTOR_STRING::iterator iNameTor;
	iNameTor = unique(vecNames.begin(), vecNames.end());

	cout << "after unique(), contents are:" << endl;
	printVec(vecNames);

	cout << "unique return a iterator, point to the first Duplicate element " << endl;
	cout << iNameTor - vecNames.begin() << endl << endl;

	vecNames.erase(iNameTor, vecNames.end()); //删除重复元素
	cout << "after erase(), contents are:" << endl;
	printVec(vecNames);
}