读懂报错 Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in G:wam.....

错误截图

报错源代码

<?php 
    require("header.php");

    $sql = "SELECT entries.*, catetogries.cat FROM entries, catetogries
        WHERE entries.cat_id = catetogries.id
        ORDER BY dateposted DESC
        LIMIT 1;";
    $result = mysql_query($sql);
    $row = mysql_fetch_assoc($result);
    echo "<h2><a href="viewentry.php?id=".$row["id"]."">".$row["subject"]."</a></h2><br />";
    echo "<i>In <a href="viewcat.php?id=".$row["cat_id"]."">".$row["cat"]."</a> - Posted on ".date("D js F Y g.iA",strtotime($row["dateposted"]))."</i>";
    echo "<p>";
    echo nl2br($row["body"]);
    echo "</p>";



    require("footer.php");
    ?>

指mysql_fetch_assoc()需要一个参数句柄作为源，但是这个传进来的是一个布尔值，即没读取到数据

即：

sql语句出错！！！

查询了下sql数据库，发现数据表名字是catetories，而并非catetogries，修改后即可读取数据