样例输入: | 3
10
81
0
</pre></td></tr><tr style="margin:0px; padding:0px; list-style-type:none; height:26px"><td class="grid_left_td" style="margin:0px; padding:6px 3px 3px; list-style-type:none; word-break:break-all; word-wrap:break-word; font-family:"Microsoft YaHei",Arial,Helvetica,sans-serif!important; border-right-style:solid; border-right-width:1px; border-right-color:rgb(238,238,238); font-size:14px; border-bottom-style:solid; border-bottom-width:1px; border-bottom-color:rgb(238,238,238)">样例输出:</td><td style="margin:0px; padding:6px 3px 3px; list-style-type:none; word-break:break-all; word-wrap:break-word; font-family:"Microsoft YaHei",Arial,Helvetica,sans-serif!important; font-size:14px; border-bottom-style:solid; border-bottom-width:1px; border-bottom-color:rgb(238,238,238)"><pre style="margin-top:0px; margin-bottom:10px; padding:9.5px; list-style-type:none; white-space:pre-wrap; word-wrap:break-word; line-height:1.42857143; overflow:auto; font-family:Menlo,Monaco,Consolas,"Courier New",monospace; font-size:13px; word-break:break-all; background-color:rgb(245,245,245); border:1px solid rgb(204,204,204)">1
5
40
</pre></td></tr></tbody></table>
两种方式处理,注意下面代码中输入不确定的n个数以0结束输入的方法:
//方法一:找到规律就这么简单n/2
void fun1() {
int n;
//注意这里输入不确定个整数,以0结束的输入方式
while (cin >> n, n) {
if (n < 0)
break;
cout << n / 2 << endl;
}
}
//方法二:
int fun2(int n) {
int remainder = 0;
int divisor = 0;
int count = 0;
while (n / 3) {
divisor = n / 3;
remainder = n % 3;
count += divisor;
n = divisor + remainder;
}
//如果最后还剩两个空瓶子,可以向老板借一个
//空瓶子再买一瓶
if (n % 3 == 2)
count += 1;
return count;
}
int main() {
//fun1();
int n;
while (cin >> n) {
if (n != 0) {
cout << fun2() << endl;
}
else
break;
}
return 0;
}
|